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moses638
02.03.2020 •
Mathematics
On a six-question multiple-choice test there are five possible answers for each question, of which one is correct and four are incorrect. If a student guesses randomly, find the probability of (a) being correct on three questions, (b) being correct on four questions, (c) being correct on all six questions.
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Ответ:
Step-by-step explanation:
given that on a six-question multiple-choice test there are five possible answers for each question, of which one is correct and four are incorrect
By mere guessing probability for choosing correct answer = p = 0.2
also each question is independent of the other
Hence if X is the number of correct questions then
X is binomial with p = 0.2 and n = 6
a) being correct on three questions,
=![P(X=3) = 0.08192](/tpl/images/0531/0919/2b750.png)
(b) being correct on four questions,
=![P(X=4) = 0.01536](/tpl/images/0531/0919/f3763.png)
(c) being correct on all six questions
=![P(x=6) = 0.000064](/tpl/images/0531/0919/d7137.png)
Ответ:
16 ounces in a pound, so (for E)
(2100)+(1600/16) = 2200 pounds