Mathematics: PLEASE HELP 25 MINUTES LEFT 38 Marlene wrote an arithmetic sequence where al = 8 and the common difference is -3. What is a rule for the nth term of this sequence?

ANSWEREXPLANATIONWe want to simplifyWe rewrite in exponential form to get:Recall the quotient rule of exponents:We apply this rule to get:Simplify:...

PLEASE HELP 25 MINUTES LEFT 38 Marlene wrote an arithmetic

Ответ:

speresenko

18.08.2021

Mathematics

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 8 and d = - 3 , then

$a_{n}$ = 8 - 3(n - 1) = 8 - 3n + 3 = - 3n + 11 → D

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Ответ:

ryleerose255

24.12.2020

Mathematics

ANSWER

$\frac{ \sqrt{2} }{ \sqrt[3]{2} } = \sqrt[6]{2}$

EXPLANATION

We want to simplify

$\frac{ \sqrt{2} }{ \sqrt[3]{2} }$

We rewrite in exponential form to get:

$\frac{ \sqrt{2} }{ \sqrt[3]{2} } = \frac{ {2}^{ \frac{1}{2} } }{{2}^{ \frac{1}{3} } }$

Recall the quotient rule of exponents:

$\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}$

We apply this rule to get:

$\frac{ \sqrt{2} }{ \sqrt[3]{2} } = {2}^{ \frac{1}{2} - \frac{1}{3} }$

Simplify:

$\frac{ \sqrt{2} }{ \sqrt[3]{2} } = {2}^{ \frac{3 - 2}{6} }$

$\frac{ \sqrt{2} }{ \sqrt[3]{2} } = {2}^{ \frac{1}{6} }$

$\frac{ \sqrt{2} }{ \sqrt[3]{2} } = \sqrt[6]{2}$

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PLEASE HELP 25 MINUTES LEFT 38
Marlene wrote an arithmetic sequence where al
=
8 and the common difference is -3.
What is a rule for the nth term of this sequence?

Ответ:

Ответ:

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