PLEASE HELP ASAP, BRAINLEST Indicate the equation of the line, in standard form, that passes through (2, -4) and has a slope of 3/5.

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equation in standard form is  -3x + 5y = -26

Step-by-step explanation:

standard form of equation of line is

Ax + By = C

where A,B and C are integers.

such line has slope -A/B

Another form of line equation is slope intercept form, which can be written as

y = mx+ c

since in problem m = 3/5

thus, equation is

y = 3/5 x + c

Given that (2,-4) passes through this line, this point will satisfy the above equation

-4 = 3/5 *2 + c

=> - 4 = 6/5 + c

=> c = -4 -6/5 = (-4*5 - 6)/5

=> c = (-20 - 6)/5 = -26/5

Thus, equation in slope intercept form is

y = 3/5 x -26/5

lets rewrite this equation in  Ax + By = C

Multiplying LHS and RHS by 5 we have

5y =( 3/5 x)* 5 - (26/5 * 5)

=> 5y = 3x - 26

we have to bring 3x on LHS for that

we subtract 3x from both side

5y  -3x = 3x - 26 -3x

=> 5y  -3x =  - 26

rearranging the equation

-3x + 5y = -26

Thus, equation in standard form is  -3x + 5y = -26

x = -2 ± i√6

Step-by-step explanation:

Simplify the equation into a proper form to complete the square.

-10 = x² + 4x

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of b

Add the term to each side of the equation.

-10 + 2² = x² + 4x + 2²

Simplify the equation.

-6 = x² + 4x + 4

Factor the perfect trinomial square into (x + 2)²

(x + 2)² = -6

Solve for x.

x = -2 ± i√6

good luck, hope this helps :)