PLEASE HELP IM BEGGING. I SUCK AT PROBABILITY 1. Paolo has plans to meet his friend for lunch at noon. The trip will take him 12 minutes by bus, and buses run every 5 minutes. If he gets to the bus stop at 11:45, what is the probability that he will arrive on time to meet his friend? Draw a picture and calculate the probability that Paolo will meet his friend on time. Explain your strategy. (Hint: Use a line segment with a length that represents the probability of Paolo being on time as 1.)

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Ответ:

pineapplepizaaaaa

19.02.2021

Mathematics

s = 0.0394

Step-by-step explanation:

Given:

0.612 0.523 0.606 0.631 0.584 0.592 0.644 0.597 0.639 0.607 0.564 0.673

Required

Calculate the sample standard deviation

First, calculate the mean

$\bar x = \frac{\sum x}{n}$

$\bar x = \frac{0.612 +0.523 +0.606 +0.631+ 0.584 + 0.592+ 0.644 +0.597 +0.639 +0.607 +0.564+ 0.673}{12}$

$\bar x = \frac{7.272}{12}$

$\bar x = 0.606$

The sample standard deviation is then calculated using:

$s = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sum (x - \bar x)^2 = (0.612 -0.606)^2+(0.523 -0.606)^2+(0.606 -0.606)^2+(0.631 -0.606)^2+(0.584 -0.606)^2+(0.592 -0.606)^2+(0.644 -0.606)^2+(0.597 -0.606)^2+(0.639 -0.606)^2+(0.607 -0.606)^2+(0.564 -0.606)^2+(0.673 -0.606)^2$

$\sum (x - \bar x)^2 = 0.017098$

So, we have:

$s = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$s = \sqrt{\frac{0.017098}{12-1}}$

$s = \sqrt{\frac{0.017098}{11}}$

$s = \sqrt{0.00155436363}$

s = 0.0394 -- approximated

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