Please help this sat math problem got me stumped

Ответ:

makayladurham19

03.02.2022

option A

Step-by-step explanation:

$3x-y=12\\ =3x = 12+y\\=x=\frac{y+12}{3}$

Putting the value of x in $\frac{8^{x} }{2^{y} }$ gives :-

$\frac{8^\frac{y+12}{3} }{2^y} = \frac{2^3(\frac{y+12}{3} )}{2^y} = \frac{2^{y+12} }{2^y} = 2^{y+12-y}=2^{12}$

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evan67

22.03.2021

The diagonal is 39.54 in

Step-by-step explanation:

First we use the Pythagorean theorem to calculate the length of the diagonal of the base.

If the base measures 13 inches by 35 inches then the diagonal is:

$c = \sqrt{13^2 +35^2}\\\\c= 37.34\ in$

Now we use the Pythagorean theorem again to find the diagonal of the cube.

If the height of the box is 13 inches and the diagonal of the base is 37.34 inches then the diagonal of the cube will be

$z = \sqrt{37.34^2 +13^2}\\\\z= 39.54\ in$

The baton will fit in the box if it is placed in the direction of the diagonal of the cube, since:

39.54\ in > 38 inches

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