Please help with triangle proportionality! For which segment lengths is AC¯¯¯¯¯ parallel to DE¯¯¯¯¯?
AD=2, DB=4, CE=3, EB=6
AD=2, DB=3, CE=6, EB=9
AD=2, DB=5, CE=4, EB=7
Select Parallel or Not parallel for each set of given information.
(Photo Attached)
Thank you!

Please help with triangle proportionality!

For which segment lengths is AC¯¯¯¯¯ parallel to DE¯¯¯

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Ответ:

mayhy100

30.12.2021

Mathematics

$\boxed{\sf sinX =\frac{21}{29}}$

Step-by-step explanation:

We need to find out the value of sinX using the given triangle . Here we can see that the sides of the triangle are 21 , 29 and 20.

We know that the ratio of sine is perpendicular to hypontenuse .

$\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}$

Here we can see that the side opposite to angle X is 21 , therefore the perpendicular of the triangle is 21. And the side opposite to 90° angle is 29 . So it's the hypontenuse . On using the ratio of sine ,

$\sf\longrightarrow sinX =\dfrac{ p}{h}=\dfrac{ZY}{ZX}$

Substitute the respective values ,

$\sf\longrightarrow \boxed{\blue{\sf sin\ X =\dfrac{21}{29}}}$

Hence the required answer is 21/29 .

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Please help with triangle proportionality! For which segment lengths is AC¯¯¯¯¯ parallel to DE¯¯¯¯¯? AD=2, DB=4, CE=3, EB=6 AD=2, DB=3, CE=6, EB=9 AD=2, DB=5, CE=4, EB=7 Select Parallel or Not parallel for each set of given information. (Photo Attached) Thank you!