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Step-by-step explanation:From the question we are told that:Mean Flaws Distance Generally the equation for Poisson mean lambda over 1000 is mathematically given by Therefore...

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mccdp55

14.12.2020

Mathematics

Sure I’ll subscribe

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laurentsupreme

14.12.2020

Mathematics

omg tysm and i def will :)

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ant5784tgi

04.03.2020

Mathematics

P(X = 4) =0.133

Step-by-step explanation:

From the question we are told that:

Mean $\x=0.6/100$

Flaws f=4

Distance d_2=1000ft

Generally the equation for Poisson mean lambda over 1000 is mathematically given by

$\lambda=0.6*1000/100$

$\lambda = 6$

Therefore

$P(X = 4) = {e^-\lambda * \lambda^{\=x}} {{\=x}!}$

$P(X = 4) =\frac{ e^{-6} * 6^4}{ 4!}$

P(X = 4) =0.133

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