PLS HELP GRAPHING ALGEBRA There are 3 people, Amber,Carter, and Ben.
PLEASE GRPAH THEM
Amber's functions: f(3)=3(4)^3 and graph f(10)=3(4)^10
Carter's functions: f(3)= 10(2)^3 and graph f(10)= 10(2)^2
Ben's functions: f(3)= 2(3)^3 and graph f(10)=2(3)^10
PLEASE DO IT ASAP
ASK QUESTIONS IF NEEDED

1. 2*(3)^x This is because he starts off with two friends (so it's times 2) and each person shares it with 3 people (the 3) each day (x is time in days)

2. The same thing but different numbers, this time it's 10 people at first but only sharing to 2 people

10*(2)^x

3. Can't help you on this one, just use a graphing software or something or whatever they tell you to use

The first three points are given to you for Ben, but for Carter its

Day  # of Shares

0      10

1      20

2      40

4. Plugin x values for 3 and 10

Ben: 2(3)^3 = 54 and 2(3)^10 = 118098

Carter: 10(2)^3 = 80 and 10(2)^10 = 10240

Amber: 3(4)^3 = 192 and 3(4)^10 = 3145728

5. The original graph and the new graph of Amber is the same except for that the graph is moved up 45 units up because Amber shared it with 45 people flat at her grandma's living facility

6. Amber's post obviously grows the fastest. This is true because she has the greatest growth value and she also has a good headstart of 45 elderly people.

7. This one is up to you, if you want more views in general then just agree with Amber, but if you want less view but with a good starting amount, then agree with Carter. Ben is a good mix if you can't decide or don't care

Step-by-step explanation:

are you a girl because if so are you single

Right or positively skewed

Step-by-step explanation:

From the median and the interquartile range we can find the first and third quartile values Q3=40.15+(4.98/2)=42.64 and Q1=37.66.

Now we have enough evidence to conclude that is Right or positively skewed

1. The mean is above the median

2. The mean is 43.70, which is above the third quartile (42.64), meaning that after the mean there's less than 30% of the data.

The evidence suggests that most of the data is concentrated at the bottom of the distribution making it right or positively skewed.