Plz guys help me please

G(-4,2), H(-3,-4), J(-1,1)

Step-by-step explanation:

The x-values would all become negative.

G(-4,2), H(-3,-4), J(-1,1)

  27.52 units

Step-by-step explanation:

The area of the 16-gon is 16 times the area of one of the sector triangles, so is ...

  16-gon area = 16×(1/2)bh = 8bh = 8(1.17 units)(2.94 units) = 27.5184 units²

  ≈ 27.52 units²

The circle area will be larger than the inscribed polygon and smaller than the circumscribing polygon. We have assumed the problem is describing an inscribed 16-gon, so the actual circle area can be estimated to be slightly larger than 27.52 units².

Comments on this answer and on the geometry

This is (presumably) the area of an inscribed 16-gon, so its area will be smaller than the area of the circumscribing circle.

We can figure the radius of the circle using the Pythagorean theorem:

  r² = h² +(b/2)² = (2.94 units)² +(0.585 units)² = 8.985825 units²

The area of the circumscribing circle is π times this, ...

  A = πr² ≈ 28.23 units²

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If we take the "height" of the sector to be the radius of the circle we are estimating, then the circle area is ...

  A = πr² = π(2.94 units)² ≈ 27.14 units² . . . . . . using 3.14 for π

Interestingly, this matches the smallest answer choice exactly. That is, the circle inscribed within the 16-gon has this area.

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Since a sector has a curved edge, we're not quite sure what the "base of one sector" is measuring. If it is 1/16 of the circumference of the circle, then the circle has an area of about 27.89 units². Then, we have no idea what the 2.94 is a measure of, since the circle's radius is 2.98 units. A 16-gon inscribed in this circle will have an apothem of 2.92 units.