Mathematics: Plz i have exam i need the answers anyone

Plz i have exam i need the answers anyone

jaylene12345678910

29.06.2021

$h^{-1}(x)=\frac {3x + 1}{5}$

Step-by-step explanation:

Given function is:

$h(x) = \frac{5x-1}{3}$

STEP 1: Replace h(x) by y, so the above function becomes:

$y = \frac{5x-1}{3}$

STEP 2: Now, replace all x with y and all y with x, we find:

$x = \frac{5y-1}{3}$

STEP 3: Solve for y

3x =5y-1

$\therefore 3x + 1=5y$

$\therefore \frac {3x + 1}{5}=y$

$\implies y=\frac {3x + 1}{5}$

STEP 4: Finally replace y with $h^{-1}(x)$ , we find:

$h^{-1}(x)=\frac {3x + 1}{5}$

This is the required inverse function of h(x).

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