PQRS is dilated with a scale factor of 2, with the dilation centered at the origin. If P is at (-4, -2), where is the corresponding point P' after the dilation? a (-2, -1) b (-8, -4) c (4, 2) d (-6, -4)

Step-by-step explanation:

Long way:

Find the midpoint (M) of AB, find the slope(m) of the line AB, then find the equation of the line through M with slope -1/m, which is the perpendicular bisector of AB.

Short way:

The perpendicular bisector of (x₁,y₁) and (x₂,y₂): 2(x₂-x₁)x + 2(y₂-y₁)y = x₂²-x₁²+y₂²-y₁².

Here this is 2(1-(-4))x + 2(6-4)y = 1²-(-4)²+6²-4² which is 10x + 4y = 5.