sydney673
22.08.2019 •
Mathematics
Prove by contradiction, that at least one of the numbbe a,a, an is greater than or equal to their average given by aat a2 t.+an). hint: start by assuming that none of the numbers is greater than or equal to a, hence ai ? a, a·a, an
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Ответ:
-112x-168y, 6(6a-1).
Step-by-step explanation:
-14(8x+12y)
-112x-168y
36a-6
6(6a-1)