Mathematics: Prove that the minimum value of (x-a)^2 + (x-b)^2 occurs when x=a+b/2. what is the minimum value?

Prove that the minimum value of (x-a)^2 + (x-b)^2

Ответ:

anikalee

13.03.2022

The function f(x)= (x-a)^2 has a minimum value at that point where f(x)=0 and if the solution of f(x)=0 is x=c, f'(c) is positive. f(x)= 2*(x-a)+2*(x-b) f'(x)=2+2=4 which is always positive f(x)=0 => 2*(x-a)+2*(x-b) => 2x-2a+2x-2b

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Ответ:

brandyrushing3

27.04.2021

Mathematics

The answer is B.

Step-by-step explanation:

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