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aarrobic
10.01.2022 •
Mathematics
Pythagor triangle exercice pls
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Ответ:
Exercise 1: AB = √39
Exercise 2: Perimeter = 68
Step-by-step explanation:
Exercise 1Let's solve for CD using the Pythagorean Theorem
Solve for CD:Let CD = b
a² + b² = c²
5² + b² = 9
25 + b² = 81
b² = 81 - 25
b = √56
We can simplify the radical: √56
= √8 * √7
= 2√2 * √7
= 2√14
Solve for ABCB = 1/2 CD
CB =![\frac{2\sqrt{14}}{2}](/tpl/images/2614/8513/3d753.png)
CB =![\sqrt{14}](/tpl/images/2614/8513/1f959.png)
Use the pythagorean theorem, let c = AB
a² + b² = c²
5² + (√14)² = c²
25 + 14 = c²
c =![\sqrt{39}](/tpl/images/2614/8513/7b476.png)
AB =![\sqrt {39}](/tpl/images/2614/8513/035b0.png)
Exercise 2Let's image a rhombus so that the diagonals are vertical and horizontal. You can see that the point of intersection of the two diagonals from 4-90° angles, and the diagonals form 4 congruent right triangles.
We can find the hypotenuse of one triangle, and multiply by 4 to find the perimeter.
Find the hypotenusea² + b² = c²
a = 1/2(30) = 15
b = 1/2(16) = 8
15² + 8² = c²
225 + 64 = c²
289 = c²
c = √289
c = 17
Find the PerimeterNow we must multiply by 4 to find the perimeter
17 x 4 = 68
Perimeter = 68
-Chetan K
Ответ:
45w
Step-by-step explanation:
Negative and Negative makes a positive