Quadrilateral pqrs has vertices at the point p(1,0),

Ответ:

mcaninch36

18.01.2022

-2 is the slope of PS

Step-by-step explanation:

Slope for the given two points (x_1, y_1) and (x_2, y_2) is given by:

$\text{Slope} = \frac{y_2-y_1}{x_2-x_1}$

As per the statement:

Quadrilateral PQRS has vertices at the point P(1,0), Q(3,-1), R(3,-3), and S(2,-2).

We have to find the slope of PS.

Coordinate of P and S are:

P(1, 0) and S(2, -2)

then by using slope formula we have;

$\text{Slope of PS} = \frac{-2-0}{2-1}$

⇒ $\text{Slope of PS} = \frac{-2}{1}$

⇒ $\text{Slope of PS} = -2$

Therefore, the slope of PS is, -2

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