Question 13 of 20 : Select the best answer for the question.
13. Find the distance between the points (-1/2,-8) and (-1/2,-2).
O A. 6
O B.1/2
O C. 10
O D. 8
Mark for review (Will be highlighted on the review page)
<< Previous Question
Next Question >>

a) 6

Step-by-step explanation:

distance formula = the sq rt of the (difference of the y-values)² + (difference of the x-values)²

=

=

= 6

Let's simplify \sqrt{75}

75

​  square root of, 75, end square root by removing all perfect squares from inside the square root.

We start by factoring 757575, looking for a perfect square:

75=5\times5\times3=\blueD{5^2}\times375=5×5×3=5

2

×375, equals, 5, times, 5, times, 3, equals, start color blueD, 5, start superscript, 2, end superscript, end color blueD, times, 3.

We found one! This allows us to simplify the radical:

\begin{aligned} \sqrt{75}&=\sqrt{\blueD{5^2}\cdot3} &=\sqrt{\blueD{5^2}} \cdot \sqrt{{3}} &=5\cdot \sqrt{3} \end{aligned}

75

​  

​  

=

5

2

⋅3

​  

=

5

2

​  ⋅

3

​  

=5⋅

3

​  

​  

So \sqrt{75}=5\sqrt{3}

75

​  =5

3

​  square root of, 75, end square root, equals, 5, square root of, 3, end square root.Let's simplify \sqrt{75}

75

​  square root of, 75, end square root by removing all perfect squares from inside the square root.

We start by factoring 757575, looking for a perfect square:

75=5\times5\times3=\blueD{5^2}\times375=5×5×3=5

2

×375, equals, 5, times, 5, times, 3, equals, start color blueD, 5, start superscript, 2, end superscript, end color blueD, times, 3.

We found one! This allows us to simplify the radical:

\begin{aligned} \sqrt{75}&=\sqrt{\blueD{5^2}\cdot3} &=\sqrt{\blueD{5^2}} \cdot \sqrt{{3}} &=5\cdot \sqrt{3} \end{aligned}

75

​  

​  

=

5

2

⋅3

​  

=

5

2

​  ⋅

3

​  

=5⋅

3

​  

​  

So \sqrt{75}=5\sqrt{3}

75

​  =5

3

​  square root of, 75, end square root, equals, 5, square root of, 3, end square root.