Mathematics: Question 5b) please, what have i done wrong? 2(x+3)(x+4)/(x+1)(x-5) x (x+1)/4(x+3)

Question 5b) please, what have i done wrong? 2(x+3)(x+4)/(x+1)(x-5)

volleyballfun24

21.01.2022

At the denominator you have

(x-5)×4=4x-20.

But:

2(x+4)/(4(x-5))=(x+4)/2/(x-5)

0,0(0 оценок)

yalley1982

21.01.2022

see explanation

Step-by-step explanation:

Given

$\frac{2(x+3)(x+4)}{(x+1)(x-5)}$ × $\frac{(x+1)}{4(x+3)}$

Cancel the common factors (x + 1), (x+3) on the numerator/ denominator

and cancel 2 and 4 on the numerator/ denominator by 2

= $\frac{x+4}{2(x-5)}$

0,0(0 оценок)

xDoxing

09.10.2020

nope /:

Step-by-step explanation:

0,0(0 оценок)