Mathematics: Rewrite the equation x^2 + 28x+ 193.5 = 0 in the form (x-p)^2 = q

Rewrite the equation x^2 + 28x+ 193.5 = 0 in the

Ответ:

heybrothwrlogan

14.02.2022

${(x + 14)}^{2} = 2.5$

Step-by-step explanation:

It can be rewritten only in the form of (x + p)^2 = q and not in (x-p)^2 = q because middle term of the given quadratic equation is positive.

${x}^{2} + 28x + 193.5 = 0 \\ \\ {x}^{2} + 28x = - 193.5 \\ \\ {x}^{2} + 2 \times x \times 14 + {(14)}^{2} = {(14)}^{2} - 193.5 \\ \\ (x + 14)^{2} = 196 - 193.5 \\ \\ {(x + 14)}^{2} = 2.5$

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Ответ:

dynamicstudent

09.06.2023

Mathematics

It's A.) linear

Step-by-step explanation:

The power of x is equal to one, making it linear [ f(x) = 2x^1 ]

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Rewrite the equation x^2 + 28x+ 193.5 = 0 in the form (x-p)^2 = q

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