Mathematics: Rewrite the radical as a rational exponent. 3√2 7

Rewrite the radical as a rational exponent. 3√2 7

rachylt8152

11.03.2022

For this case we have:

By property of the radicals: $\sqrt {n} = n ^ {\frac {1} {2}}$

Given $3 \sqrt {27}$

We can rewrite it as:

$3 \sqrt {(3 * 3 * 3)} =\\3 \sqrt {(3 ^ 2 * 3)}$

We know that by property of the radicals:

$\sqrt {n * m} = \sqrt {n} * \sqrt {m}$ , then:

$3 \sqrt {(3 ^ 2 * 3)} = 3 (\sqrt {3 ^ 2} *\sqrt {3})$

Simplifying, considering that $\sqrt {9} = 3$ , we have:

$3 * 3 * \sqrt {3} =\\9 \sqrt {3} =\\9 * (3) ^ {\frac {1} {2}}$

$3 \sqrt {27} = 9 * (3) ^ {\frac {1} {2}}$

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knela

22.09.2020

Step-by-step explanation:

substitue values in the table into the equation.

x = 2, then y = 4(2)-3 =>

y= 5

y = -3, then -3 = 4x-3 =>

x = 0

x = -1, then y = 4(-1) - 3 =>

y = -7

x = 3, then y = 4(3) -3 =>

y = 9

y = 1, then 1 = 4x - 3 =>

x = 4

now plot all of these points and create a line from them

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