Mathematics: Ryan finds the surface area of the box. how much wrapping paper is needed if the box measures 9 in. by 4 in. by 6 in?

Radius of the cone = Step-by-step explanation:Volume of a cone: For volume=321 feet^3 andHeight= 6 feetAs, So , So, the Radius of the cone is...

Ryan finds the surface area of the box. how much

allierl2001

14.05.2020

Radius of the cone = $\sqrt{51.12}feet$

Step-by-step explanation:

Volume of a cone:

$\pi *r^2*\frac{h}{3}$

For volume=321 feet^3 and

Height= 6 feet

$321=\pi *r^2*\frac{h}{3}$

As, $\pi =\frac{22}{7}=3.14$

So ,

$321=3.14*r^2*\frac{6}{3}$

$321=3.14*2*r^2\\\\321=6.28*r^2\\\\r^2=321/6.28\\\\r^2=51.12\\\\r=\sqrt{51.12}feet$

So, the Radius of the cone is $\sqrt{51.12}feet$

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