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21.07.2020 •
Mathematics
Select the correct answer. What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)? A. x2 + y2 − 4x + 2y + 1 = 0 B. x2 + y2 + 4x − 2y + 1 = 0 C. x2 + y2 + 4x − 2y + 9 = 0 D. x2 − y2 + 2x + y + 1 = 0
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Ответ:
x^2 +4x + y^2 -2y +1 =0
Step-by-step explanation:
First we need to find the radius
Since the y coordinate is the same, the radius is the difference in the x coordinate -2 - (-4) = -2+4 = 2
A circle can be written in the form
(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius
(x--2)^2 + (y-1)^2 = 2^2
(x+2)^2 + (y-1)^2 = 4
FOIL ing
x^2 +4x+4 + y^2 -2y +1 = 4
Combining like terms
x^2 +4x + y^2 -2y +5 -4 =0
x^2 +4x + y^2 -2y +1 =0
Ответ:
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Step-by-step explanation: