Seth is using the figure shown below to prove pythagorean theorem using triangle similarity: in the given triangle abc, angle a is 90° and segment ad is perpendicular to segment bc. the figure shows triangle abc with right angle at a and segment ad. point d is on side bc. which of these could be a step to prove that bc2 = ab2 + ac2? (6 points) a) by the cross product property, ab2 = bc multiplied by bd. b) by the cross product property, ac2 = bc multiplied by bd. c) by the cross product property, ac2 = bc multiplied by ad. d) by the cross product property, ab2 = bc multiplied by ad. *i think the answer could be d but i'm not sure.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

The correct option is ΔABC ≅ ΔFED by SAS

Step-by-step explanation:

Looking at the given diagram,

Side AC = Side DF = 3.2

Side AB = Side FE = 4 units

Angle A = angle F = 72 degrees

Since two sides and one angle are equal, then triangle FED = triangle ABC by SAS(side angle side)

This makes the ratios possible

AB/FE = AC/DF

The HL given means hypotenuse leg. It will not hold because the triangles are not right angle triangles.