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barattah

barattah

03.03.2021 •

Mathematics

Show that (4p^2-3q)^2+48p^2q =(4p^2+3q^2)

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Ответ:

deaishaajennings123

02.04.2021

Given:

The statement is

(4p^2-3q)^2+48p^2q=(4p^2+3q^2)

To prove:

The given statement.

Solution:

We have,

(4p^2-3q)^2+48p^2q=(4p^2+3q^2)

Now,

LHS=(4p^2-3q)^2+48p^2q

Using (a-b)^2=a^2+b^2-2ab , we get

LHS=(4p^2)^2+(3q)^2-2(4p^2)(3q)+48p^2q

LHS=(4p^2)^2+(3q)^2-24p^2q+48p^2q

LHS=(4p^2)^2+(3q)^2+24p^2q

It can be rewritten as

LHS=(4p^2)^2+(3q)^2+2(4p^2)(3q)

Using (a+b)^2=a^2+b^2+2ab , we get

LHS=(4p^2+3q^2)

LHS=RHS

Hence proved.

0,0(0 оценок)

Ответ:

alethhaaa

10.07.2022

its 0 :)

Step-by-step explanation:

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