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[a+x]ⁿ=aⁿ[1+×/a]ⁿ, a≠0

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Lia97

20.03.2021

Mathematics

$Proof~that~(a+x)^n=a^n(1+\frac{x}{a})^n\\R.H.S. = a^n(1+\frac{x}{a})^n = [a(1+\frac{x}{a})]^n [a^nb^n=(ab)^n] \\~~~~~~~~~~~= (a+x)^n =L.H.S. ~proved$

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stelllllllllllllllla

12.06.2020

Mathematics

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