Similar triangle question

Step-by-step explanation:

line A can be written as y1= 3/4.x -5/4

line B is a linear function : y2= ax +b

4a+b=7 and -a +b =3 so a=4/5 and b=19/5

so y2=4/5x +19/5

so they are not parallel

Line A goes through (0,-5/4) and (1,-1/2)

Gradient of line A = G1= (-1/2 - (-5/4))/(1-0) =3/4=0.75

Gradient of line B= G2= (7/3)/(4-(-1))=4/5=0.8