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Daryn121504
27.08.2020 •
Mathematics
Simple Algebra question! Find an expression equivalent to (\frac{3x^3}{y^3})^3
1. \frac{9x^6{} }{3y}
2. \frac{9x^9{} }{y^3}
3. \frac{9x^6{} }{y^3}
4. \frac{27x^6{} }{3y}
5. \frac{27x^9{} }{y^3}
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Ответ:
I believe thatit may be 2. I'm not that good with math sorry if it's not correct
Ответ:
(a)![13.046<\mu< 22.15](/tpl/images/0173/3808/c343b.png)
(b) The best point estimate of
is the sample mean ![=17.598](/tpl/images/0173/3808/313ee.png)
The margin of error = 4.552
Step-by-step explanation:
Given : The confidence interval for the population mean = (13.046 , 22.15)
Sample mean :![\overline{x}=17.598](/tpl/images/0173/3808/fa4e4.png)
Standard deviation :![\sigma= 16.01712719](/tpl/images/0173/3808/076fe.png)
Sample size :![n=50](/tpl/images/0173/3808/7629d.png)
a. Let
represents the population mean.
Then we can write the confidence interval for the population mean as :-
b. The best point estimate of
is the sample mean ![=17.598](/tpl/images/0173/3808/313ee.png)
Also, the lower limit of confidence interval can be written as
i.e.![\overlien{x}-E=13.046](/tpl/images/0173/3808/62d68.png)
Hence, the margin of error = 4.552