Simplify the expression by combining like terms . 2(3t + 4) + 6(t + 2)

2(3t + 4) + 6(t + 2)

First, distribute. The Distributive Property: a(b + c) = ab + ac. Distribute 2 and 6 to get rid of the parentheses.

2(3t + 4) + 6(t + 2)

6t + 8 + 6(t + 2)

6t + 8 + 6t + 12

Collect like terms (constants and variable terms).

6t + 8 + 6t + 12

12t + 20

The expression now has one variable term and one constant; it cannot be simplified further.

12t + 20

Distribute 2 to 3t and 4, and 6 to t and 2

2(3t + 4) = 6t + 8

6(t + 2) = 6t + 12

Combine like terms:

6t + 8 + 6t + 12 = 12t + 20

12t + 20 is your answer

hope this helps

a) f(x) has a maximum vertex

b) g(x) has a minimum vertex

Step-by-step explanation:

The function

has its vertex at (h,k).

If a>0, then (h,k) is a minimum vertex.

If a<0, then (h,k) is a maximum vertex.

The first function is

a=-1<0, therefore the vertex (1,5) is the maximum point.

The second function is

a=1>0, therefore the vertex (-2,-3) is a minimum point.