Mathematics: Simplify (x^(2)+y^(2))/(x^(2)-y^(2))+(y)/(x+y)-(x)/(x-y)

Simplify (x^(2)+y^(2))/(x^(2)-y^(2))+(y)/(x+y)-(x)/(x-y)

Ответ:

johnmtraegeror8m06

26.04.2021

Mathematics

The correlation coefficient between pressure and mileage is -0.1137.

The researcher was not correct in his conclusion.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).

It is a mathematical measure of certain kind of correlation, in sense a statistical relationship amid two variables. It ranges from -1 to +1.

A correlation coefficient of 0 implies that there is no relationship between the two variables.

Let X = pressure and Y = mileage.

The formula to compute the Pearson's correlation coefficient is:

$\begin{aligned}r~&=~\frac{n\cdot\sum{XY} - \sum{X}\cdot\sum{Y}} {\sqrt{\left[n \sum{X^2}-\left(\sum{X}\right)^2\right] \cdot \left[n \sum{Y^2}-\left(\sum{Y}\right)^2\right]}} \\\end{aligned}$

The values of $\sum X,\ \sum,\ \sum Y,\ \sum X^{2},\ \sum Y^{2}\ and\ \sum XY$ are computed in the table below.

Compute the correlation coefficient between pressure and mileage as follows:

$\begin{aligned}r~&=~\frac{n\cdot\sum{XY} - \sum{X}\cdot\sum{Y}} {\sqrt{\left[n \sum{X^2}-\left(\sum{X}\right)^2\right] \cdot \left[n \sum{Y^2}-\left(\sum{Y}\right)^2\right]}} \\r~&=~\frac{ 14 \cdot 15472 - 462 \cdot 469.2 } {\sqrt{\left[ 14 \cdot 15302 - 462^2 \right] \cdot \left[ 14 \cdot 15910.74 - 469.2^2 \right] }} \approx -0.1137\end{aligned}$

The correlation coefficient between pressure and mileage is -0.1137.

Since the correlation coefficient is not equal to 0, there exist a relationship between the two variables.

The correlation coefficient value is negative. This implies that there is an inverse relationship between the two variables.

That is, as the pressure increases the mileage decreases.

Thus, the researcher was not correct in his conclusion.

Underinflated or overinflated tires can increase tire wear and decrease gas mileage. A manufacturer

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Simplify (x^(2)+y^(2))/(x^(2)-y^(2))+(y)/(x+y)-(x)/(x-y)

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