Mathematics: Solve 3x2 + x + 10 = 0. round solutions to the nearest hundredth. x ≈ −2.83 and x ≈ 0.83 no real solutions x ≈ −2.01 and x ≈ 1.67 x ≈ −1.67 and x ≈ 2.01

-21x+31 this is the answer you were looking for...

Solve 3x2 + x + 10 = 0. round solutions to the - id321004514684, michaelishawilliams

samy6570

14.01.2022

No real solutions.

B is correct

Step-by-step explanation:

Given: 3x^2+x+10=0

We are given a quadratic equation and need to solve for x.

Quadratic formula: ax^2+bx+c=0

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

For our equation, a=3, b=1 and c=10

Substitute the value of a, b and c into formula

$x=\dfrac{-1\pm\sqrt{1^2-4\cdot 3\cdot 10}}{2\cdot 3}$

$x=\dfrac{-1\pm\sqrt{-119}}{6}$

Here, Roots are imaginary because number inside the square root is negative.

Hence, No real solutions.

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