Mathematics: Solve for n: 4^n×2^-18=1

Solve for n: 4^n×2^-18=1 - id421817264773, Marshmallow6989

davidoj13

31.01.2022

One way to do it is by cleverly rewriting terms and using some basic algebraic identities:

$4^n\cdot 2^{-18}=1$ .

$2^{2n-18}=2^0$ .

2n-18=0 .

$n=18/2=\boxed{9}$ .

Another way would be to use logarithms, namely:

$4^n\cdot2^{-18}=1\implies n=\log_4\Big({\frac{1}{2^{-18}}}\Big)=\boxed{9}$ .

Hope this helps.

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leyslebravo2729

31.01.2022

n = 9.

Step-by-step explanation:

4^n = 1 / 2^-18

4^n = 2^18

2^2n = 2^18

2n = 18

n = 9.

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bhelsea15

04.11.2021

I think it's 4a+2, what are the different options?

If that's not it then try 4a squared + 2

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