Solve for y i have no clue i am so lost you

Ответ:

HighSchool97654

12.03.2022

In the Triangle ABD, Using Pythagoras theorem we can write

$AB^2=BD^2+AD^2\\ \\ AB^2=9^2+y^2\\ \\ AB^2=81+y^2\\ \\$

In the Triangle ACD using Pythagoras Theorem

$AC^2=AD^2+CD^2\\ \\ AC^2=y^2+7^2\\ \\ AC^2=y^2+49\\$

Now in the larger Triangle ABC, we can write

AB^2+AC^2=BC^2

Now substitute the values from the above equations we get

$81+y^2+49+y^2=(9+7)^2\\ \\ 130+2y^2=16^2\\ \\ 130+2y^2=256\\ \\ 65+y^2=128\\ \\ y^2=128-65=63\\ \\ y=\sqrt{63} =3\sqrt{7} \\$

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Roselyn0131

23.12.2022

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Step-by-step explanation:

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