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Wolfzbayne
28.01.2020 •
Mathematics
Solve the following system of equations by linear combination: 2d + e = 8 d – e = 4
select one:
a.
the solution is (5, –2).
b. the solution is (4, 0).
c. there is no solution.
d. there are an infinite number of solutions
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Ответ:
2d+e+d-e=8+4 combine like terms
3d=12 divide by 3
d=4, now use this d in either original equation to solve for e...d–e=4 so
4-e=4 subtract 4
-e=0
e=0
So the solution, where the lines intersect graphically, is the point (4, 0)
Ответ:
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