Solve the right triangle. round lengths to the nearest tenth and angles to the nearest degree

The answer to your question is:

AC length = 1.7 cm

∠A = 30.7°

∠ B = 59.3 °

Step-by-step explanation:

To find the length of AC, we use the pythagorean theorem:

c² = a² + b² but we need to find a Ac which is a leg so we clear a from the equation

a² = c² - b²

a² = 3.28² - 2.8²

a² = 10.8 - 7.8

a² = 3

a = 1.7 cm

To find ∠A we use the sine function

sine Ф = AC / AB = 1.7/3.28 = 0.51

Then ∠A = sine-1 = 30.7°

To find ∠B = 180 - 90- 30.7 = 59.3°

The answer to your question is:

AC length = 1.7 cm

∠A = 30.7°

∠ B = 59.3 °

Step-by-step explanation:

To find the length of AC, we use the pythagorean theorem:

c² = a² + b² but we need to find a Ac which is a leg so we clear a from the equation

a² = c² - b²

a² = 3.28² - 2.8²

a² = 10.8 - 7.8

a² = 3

a = 1.7 cm

To find ∠A we use the sine function

sine Ф = AC / AB = 1.7/3.28 = 0.51

Then ∠A = sine-1 = 30.7°

To find ∠B = 180 - 90- 30.7 = 59.3°

the answer is 0.0800320128 or in simplified form 0.08

Step-by-step explanation:

First you divide 12 ÷ 5.88 = 2.04081632653. Then you divide 20 ÷ 10.20 = 1.96078431373. Lastly you subtract 2.04081632653 - 1.96078431373 =  0.0800320128 or 0.08