samsavage4073
19.11.2020 •
Mathematics
Solve the system of equatior x+2y=14 x-y=13
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Ответ:
x=40/3 2/3
Step-by-step explanation:
Use elimination method for this. To do it, Multiply the x-y=13 by 2. It turns into 2x-2y=26. We have this
x+2y=14
2x-2y=26
Add because the signs are different for y each equation.
So 3x=40
x=40/3
14-40/3=2/3
y=2/3
x=40/3
Ответ: