Mathematics: solving trig. equations: csc^2x-2cot^2x=0

solving trig. equations: csc^2x-2cot^2x=0

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zavalaaria

30.12.2021

$csc^2x-2cot^2x=0;\ D:x\neq k\pi\ (k\in\mathbb{Z})\\\\\frac{1}{sin^2x}-2\cdot\frac{cos^2x}{sin^2x}=0\\\\\frac{1-2cos^2x}{sin^2x}=0\iff 1-2cos^2x=0\\\\-2cos^2x=-1\ \ \ /:(-2)\\\\cos^2x=\frac{1}{2}\\\\cosx=\sqrt\frac{1}{2}\ \vee\ cosx=-\sqrt\frac{1}{2}\\\\cosx=\frac{\sqrt2}{2}\ \vee\ cosx=-\frac{\sqrt2}{2}$

$x=\frac{\pi}{4}+2k\pi\ \vee\ x=-\frac{\pi}{4}+2k\pi\ \vee\ x=\frac{3\pi}{4}+2k\pi\ \vee\ x=-\frac{3\pi}{4}+2k\pi\\\\\\x=\frac{\pi}{4}+\frac{k\pi}{2}\ (k\in\mathbb{Z})$

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cbrpilot1151

25.09.2021

Mathematics

$6(3x-1)=8-(10x-14) \\ \\ 18x-6=8-10x+14 \\ \\ 18x-6=-10x+22 \\ \\ 28x=28 \\ \\ x=1$

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solving trig. equations: csc^2x-2cot^2x=0

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