chozz2783

chozz2783

08.03.2021 •

Mathematics

Start by writing the equation of the circle. (Recall that the general form of a circle with the center at the origin is x2 + y2 = r2. (10 points)

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Ответ:

dhdcchj

05.07.2020

(a) 160 Naira

(b) Undefined

Step-by-step explanation:

Given

Let:

$y \to$ cost of bag of rice

$x \to$ people demanding the bag

So, we have:

$y\ = \frac{k}{\sqrt x} + c$ ---- The variation

y = 100; x = 36

y = 150; x = 144

We have:

$y\ = \frac{k}{\sqrt x} + c$

When: y = 100; x = 36

$100 = \frac{k}{\sqrt {36}} + c$

$100 = \frac{k}{6} + c$ -- (1)

When: y = 150; x = 144

$150 = \frac{k}{\sqrt {144}} + c$

$150 = \frac{k}{12} + c$ --- (2)

Subtract (1) from (2)

$150 - 100 = \frac{k}{12} - \frac{k}{6} + c - c$

$50 = \frac{k}{12} - \frac{k}{6}$

Multiply through by 12

600 = k - 2k

600 = -k

k = -600

To solve for x, we have:

$100 = \frac{k}{6} + c$ -- (1)

This gives:

$100 = \frac{-600}{6} + c$

100 = -100 + c

c = 100 + 100

c = 200

So, the equation is:

$y\ = \frac{k}{\sqrt x} + c$

$y = -\frac{600}{\sqrt x} + 200$

Solving (1): y; when x = 225

We have:

$y = -\frac{600}{\sqrt x} + 200$

$y = -\frac{600}{\sqrt {225}} + 200$

$y = -\frac{600}{15} + 200$

y = -40 + 200

y = 160

Solving (2): x; when x = 200

We have:

$y = -\frac{600}{\sqrt x} + 200$

$200 = -\frac{600}{\sqrt x} + 200$

Collect like terms

$\frac{600}{\sqrt x} = 200 - 200$

$\frac{600}{\sqrt x} =0$

Cross multiply

$600 =0 * \sqrt x$

600 =0

x is undefined

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