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flowerchild44
04.01.2020 •
Mathematics
Students are given 3 minutes for each multiple-choice question and 5 minutes for each free-response question on a test. there are 15 questions on the test, and students are given 51 minutes to take it.
the system of equations shown can be used to find the number of multiple-choice questions, m, and the number of free-response questions, f, on the test.
m + f = 15
3m + 5f = 51
how many multiple-choice questions are on the test?
3
5
12
14
Solved
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Ответ:
3m + 5f = 51 . . . (2)
(1) * (5) => 5m + 5f = 75 . . . (3)
(3) - (2) => 2m = 24
m = 24/2 = 12
Therefore, there are 12 multiple choice question on the test.
Ответ:
option C is correct.
12 multiple-choice questions are on the test
Step-by-step explanation:
Given: The system of equation :
m + f = 15 ......[1]
3m + 5f =51 .......[2]
where m is the number of multiple choice questions and f is the number of free response questions.
Now, multiply 3 to both sides of an equation in [1];
Simplify:
3m + 3f = 45
Now, subtract 3f to both sides of an equation:
3m + 3f -3f = 45 -3f
Simplify:
3m = 45 -3f ......[3]
Substitute the equation [3] in [2];
45 -3f +5f = 51
Combine like terms;
45 + 2f = 51
Subtract 45 to both sides of an equation we get;
45+ 2f -45 =51-45
Simplify:
2f = 6
Divide by 2 to both sides of an equation:
Simplify:
f = 3
Substitute the value of f = 3 in equation [1] solve for m;
m + 3 = 15
Subtracting 3 from both sides we get
m + 3 -3 = 15 - 3
Simplify:
m = 12
Therefore, the number of multiple-choice questions are on the test is; 12
Ответ:
-1.9
Step-by-step explanation:
He has $1.10 in his printing account. 0.25 each sheet of paper.
47 pages.
He printed both sides so 47:2= 23.5.
Because he printed 2 pages then we divide by 2.
23.5:2=11.75
We cannot print a half of page, so we print 12 pages.
12*0.25=3
1.10-3=-1,9
His printing account will be in minus.