Suppose an isosceles triangle abc has a = 45° and b = c = 4. what is the length of a2? a.22.63 b.54.63 c.9.37 d.3.10

Since b = c, the angles B and C also equal

 so you get
180 - 45 = 135
135/2 = =67.5 for each angle

now we know 2 sides and all 3 angles, use the law of sines to find a

b/sin B = a/sin A

4/(sin 67.5) = a/(sin 45)

a = 4(sin 45)/(sin 67.5)

a^2 = (4(sin 45)/(sin 67.5))^2

a^2 = 9.37

 Answer is C

B, and C. Let me know if i am wrong.

Step-by-step explanation: