Mathematics: Suppose that a random sample of adult males has a sample mean heart mass of x¯=310.1 grams, with a sample standard deviation of s=6.6 grams. Since adult male heart masses are generally symmetric and bell-shaped, we can apply the Empirical Rule. Between what two masses do approximately 68% of the data occur? Round your answer to the nearest tenth.

Suppose that a random sample of adult males has a

ihatemylifebutohwell

28.01.2022

Between 303.5 grams and 316.7 grams

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 310.1 grams

Standard deviation = 6.6 grams

Between what two masses do approximately 68% of the data occur?

By the Empirical Rule, within 1 standard deviation of the mean.

310.1 - 6.6 = 303.5 grams

310.1 + 6.6 = 316.7 grams

Between 303.5 grams and 316.7 grams

0,0(0 оценок)

danee376

26.12.2021

$A=301.71\ \text{inches}^2$

Step-by-step explanation:

Given that,

The radius of a cone, r = 6 inches

The slant height of the cone, l = 10 inches

We need to find the total surface area of the cone. It is given by :

$A=\pi rl+\pi r^2$

Substituting all the values,

$A=\pi r(l+ r)\\\\A=\dfrac{22}{7}\times 6\times (10+ 6)\\\\A=301.71\ \text{inches}^2$

So, the total surface area of the cone is $301.71\ \text{inches}^2$ .

0,0(0 оценок)