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JCSakura
03.04.2020 •
Mathematics
Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random sample of 1,000 people, what is the probability that sample will have a mean that is greater than $52,000?
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Ответ:
Probability that the sample will have a mean that is greater than $52,000 is 0.0057.
Step-by-step explanation:
We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.
We select a random sample of 1,000 people.
Let
= sample mean
The z-score probability distribution for sample mean is given by;
Z =
~ N(0,1)
where,
= population mean = $50,000
n = sample of people = 1,000
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
So, probability that the sample will have a mean that is greater than $52,000 is given by = P(
> $52,000)
P(
> $52,000) = P(
>
) = P(Z > 2.53) = 1 - P(Z
2.53)
= 1 - 0.9943 = 0.0057
Now, in the z table the P(Z
x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.
Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.
Ответ:
20 in.
Step-by-step explanation:
You can use similar triangle ratios to solve for this problem.
6/15=4/x, Now cross multiply to solve for x
6x=60, x=10 Find the perimeter
10+6+4=20, the perimeter of MNO is 20 in.