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mariana5493
07.04.2020 •
Mathematics
The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean of 5.6 years and a standard deviation of 1.9 years. Random samples of size 18 are drawn from the population and the mean of each sample is determined. Find the mean and the standard error.
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Ответ:
a) 5.6 years
b) 0.4478
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 5.6 years
Standard Deviation, σ = 1.9 years
Sample size, n = 18
We are given that the distribution of amounts of time is a bell shaped distribution that is a normal distribution.
a) Mean of each sample.
The best estimator of the sample mean is the population mean itself. Thus, we have:
Thus, the sample mean is 5.6 years.
b) Standard error
Formula:
Putting values, we have.
Thus, the standard error is 0.4478.
Ответ:
200
Step-by-step explanation:
The reason why this answer is 200 is because it gave us a clue that 30 students said that pie was their favorite desert, what is half of 30? 15 so therefore, the pattern is half of each.
Ice cream: 35x2=70
Cake: 27x2=54
Candy: 23x2=46
Pie: 15x2=30
So, 70+54+46+30=200