The angle of elevation to the top of the hotel is 55°. if the height of the hotel is 90 feet, about how far away is mr. jameson from the hotel?

To solve this, use SOH CAH TOA. Your angle would be at Jameson's location, meaning that the hotel's height would be your opposite side and the distance from the hotel would be your adjacent side. This gives you tan(x)=(OPP)/(ADJ). Now, isolate the adjacent part of the equation, ADJ*tan(x)=OPP, ADJ=(OPP)/(tan(x)), plug in your values, ADJ=90/(tan(55))≈90/1.428≈63.019. This means jameson is roughly 63.019 feet away from the hotel.

Part a: the approximate y-intercept of the line of best fit is (0, 4). it represents the number of matches a student might win with 0 months of practicing boxing.part b: a graphing calculator computes the line of best fit as    y = 1.63636x + 4all the given points are used in the calculation.when x=13, this gives      y = 1.63636*13 + 4 ≈ 25.27the number of matches that could be won after 13 months of practice is 25.