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29.01.2020 •
Mathematics
The area of a trapezoid is 152. the height is 16 and the length of one of the sides is 6. find the length of the second parallel side.
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Ответ:
A=h*(b1+b2)/2,
b1 an db2 are the two lengths of the sides
152 = 16*(b1+6)/2 = 8*(b1+6)=8*b1+48--> 8*b1=104, b1 = 104/8=13
A = 16*(6+13)/2=16*9.5=152
Ответ:
8mm, 10mm, 14mm
Step-by-step explanation:
we know that an obtuse triangle has one angle greater than![90^{\circ}](/tpl/images/0486/2365/34c22.png)
By using corollary to Pythagoras Theorem, we can test whether these triangles are obtuse or not .
We need to get the sum of the squares of the two shorter sides and compare with the square of the longer side.
For 8, 10, 14
⇒ An obtuse triangle.
For 9, 12, 15
⇒ A right triangle.
For 10, 14, 17
⇒ An acute triangle.
For 12, 15, 19
An acute triangle.