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artiomtyler007
03.08.2019 •
Mathematics
The center of a circle is the point (3, 2). if the point (6, −2) lies on this circle, find the standard equation for the circle.
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Ответ:
centre of circle O(3,2)=O(x0,y0)
point on circle P(6,-2)
Standard equation of circle:
(x-x0)^2+(y-y0)^2=r^2
r=radius of circle
= (distance OP)
= sqrt((6-3)^2+(-2-2)^2)
=sqrt(3^2+(-4)^2)
=sqrt(25)
=>
r^2=(sqrt(25))^2=25
Equation of circle
(x-x0)^2+(y-y0)^2=r^2
(x-3)^2+(y-2)^2=25 standard equation of circle
Ответ:
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