The distance travelled by a delivery vehicle can be calculated by the equation Distance = Rate x Time. What would be the correct representation of a situation in which a driver doubles his original speed, but drives for only of the original amount of time? dn = new distance do = original distance

New distance = 2do

Step-by-step explanation:

The distance equation :

Distance = speed * time

If speed is doubled ; time stays the same

If speed is doubled,; new speed becomes

Doubled speed = 2* speed

Time remains the same ;

Hence,

New distance becomes : 2 * speed * time

Original dista, Speed * distance

New distance, dn = 2*do = 2do

cos α = 8/17

Apply Pythagoras theorem for triangle ,

Let get unknown side of triangle is y

17^2 = 8^2 + y^2

17^2 - 8^2 =  y^2

225 = y^2

y = sqrt(225)

y = 15

tan α = 15/8

Step-by-step explanation: