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Wierdo101
03.03.2021 •
Mathematics
The doubling period of a bacterial population is 15 minutes. At time t= 80 minutes, the bacterial population was 90000
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Ответ:
unknown please expainsiate
Ответ:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
Ответ:
The midpoint of AB is (-1, 4.5)
x-coordinates: (2-4)/2 = -2/2 = -1
y-coordinates: (3+6)/2 = 9/2 = 4.5
Solution: (-1, 4.5)