jadehobbs03
18.03.2021 •
Mathematics
The employee benefits manager of a medium size business would like to estimate the proportion of full-time employees who prefer adopting plan A of three available health care plans in the coming annual enrollment period. A reliable frame of the company's employees and their tentative health care preferences are available. Using Excel, the manager chose a random sample of size 50 from the frame. There were 17 employees in the sample who preferred plan A. Construct a 99% confidence interval for the proportion of company employees who prefer plan A. Assume that the population consists of the preferences of all employees in the frame. The lower boundary is 0.172
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Ответ:
Ответ:
Let's compare side lengths (a) of the first three squares:
1. square: a₁ = 24 inches
2. square: a₂ = 19.2 inches
3. square: a₃ = 15.36 inches
Therefore, everytime Orlando reduces side length 1.25 times.
Now, let's reduce side length of 3. square 1.25 to get side length of 4. square:
4. square: a₄ = ?
⇒
⇒
⇒ a₄ = 12.288 inches
Since 12.288 inches is still more than 12 inches, we need 5. square:
4. square: a₅ = ?
⇒
⇒
⇒ a₅ = 9.83 inches
Thus, fifth square is the first square with a side length (9.83 inches) of less than 12 inches.