Mathematics: The equation -2x^2+3=-9x is rewritten in the form of -2(x-p)^2 +q=0. What is the value of q?the equation -2x^2+3=-9x is rewritten in the form of -2(x-p)^2 +q=0. What is the value of q?

8 3/4 : 3 1/235/4 : 7/2Divide each side by 7/2 so the left side becomes 1:(35/4) / (7/2) : 135/4*2/7 :170/28 :110/4 :15/2:12 1/2 :1Hope this helps :)...

The equation -2x^2+3=-9x is rewritten in the - id22395607499, keigleyhannah30

Ответ:

thetulipfox

21.01.2022

Mathematics

Value of q is $\frac{105}{8}$ .

Step-by-step explanation:

We have , the equation -2x^2+3=-9x is rewritten in the form of -2(x-p)^2 +q=0 . We need to find What is the value of q . Let's find out:

Let's simplify equation -2x^2+3=-9x into -2(x-p)^2 +q=0 :

⇒ -2x^2+3=-9x

⇒ -2x^2+9x+3=0

⇒ 2x^2-9x=3

⇒ $2(x^2-\frac{9}{2}x)=3$

⇒ $(x^2-\frac{9}{2}x)=\frac{3}{2}$

⇒ $(x^2-2(1)\frac{9}{4}x)=\frac{3}{2}$

⇒ $(x^2-2(1)\frac{9}{4}x) + (\frac{9}{4})^2=\frac{3}{2} + (\frac{9}{4})^2$

⇒ $(x-\frac{9}{4})^2=\frac{3}{2} + (\frac{81}{16})$

⇒ $(x-\frac{9}{4})^2=\frac{24}{16} + (\frac{81}{16})$

⇒ $(x-\frac{9}{4})^2=\frac{105}{16}$

⇒ $-2(x-\frac{9}{4})^2=-2(\frac{105}{16})$

⇒ $-2(x-\frac{9}{4})^2=-\frac{105}{8}$

⇒ $-2(x-\frac{9}{4})^2+\frac{105}{8} = 0$

Comparing this equation to -2(x-p)^2 +q=0 , $q =\frac{105}{8}$ .

Therefore ,Value of q is $\frac{105}{8}$ .

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The equation -2x^2+3=-9x is rewritten in the form of -2(x-p)^2 +q=0. What is the value of q?the equation -2x^2+3=-9x is rewritten in the form of -2(x-p)^2 +q=0. What is the value of q?

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