![cam1976](/avatars/37377.jpg)
cam1976
04.11.2020 •
Mathematics
The floor of a conference hall can be covered completly with tiles.Its length is 36ft. longer than its width.The area of the floor is less than 2040squ are ft.How would you represent the with of the floor?How about its lenght?What mathematical sentence would represent the given situation?What are the possible dimensions of the floor?How about the possible areas of the floor?Would it be realistic for the floor to have an area of 144sq.ft?Explain your answer.
Solved
Show answers
More tips
- F Family and Home How to Teach Your Child to Read?...
- C Computers and Internet How to Download Videos from YouTube? Simple Steps to Download Any Content...
- S Style and Beauty Tricks and Tips: How to Get Rid of Freckles...
- H Health and Medicine How to perform artificial respiration?...
- C Computers and Internet How to Get Rid of Windows Genuine Check?...
- F Food and Cooking The Disease That Haunted Abraham Lincoln...
- S Style and Beauty How to Make Your Lips Fuller? Ideas and Tips for Beautiful Lips...
- S Style and Beauty How are artificial nails removed?...
- F Family and Home How to Sew Curtain Tapes: Best Tips from Professionals...
- H Horoscopes, Magic, Divination How to Cast a Love Spell on a Guy? Guide for Guys...
Answers on questions: Mathematics
- M Mathematics When an Alvia high-speed train that is stopped in Barcelona leaves the station, its speed increases (accelerates) at a constant rate of 3, 888 kilometers per hour squared...
- M Mathematics I NEED HELP Consider the linear equation 2y - 3x = 5. 1. The pair (-1, 1) is a solution to the equation. Find another (x, y) pair that is a solution to the equation....
- H History The Leader of England during the attempted invasion of the Spanish Armada was… Elizabeth I Henry VIII James I Mary I...
- B Business A Loan is an Unlimited Resource...
Ответ:
Step-by-step explanation:
Given
Area of a floor = 2040ft²
If Its length is 36ft. longer than its width, then L = W+36
Area = LW
L is the length
W is the width
A < W(W+36)
2040 < W²+36W
0<W²+36W-2040
W²+36W-2040 >0
W = -36±√36²-4(-2040)/2
W = -36±√1296+8160)/2
W = -36±√9456/2
W = -36±97.25/2
W = -36+97.25/2
W = 61.24/2
W > 30.62ft
Since L = W+36
L > 30.62+36
L > 66.62ft
The width of the floor is 30.62ft
The length is 66.62ft
The mathematical sentence would represent the given situation is the width is greater than 30.62ft while the length must be greater than 66.62ft
The possible dimension of the floor is 31ft by 67 ft
The possible areas is 31*67 = 2077ft²
It won't be realistic to get an area of 144sqft because the initial area is greater than 144. Hence the feasible area will be greater than 2040ft²
Ответ: