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izzyisawesome5232
16.10.2020 •
Mathematics
The freshman spirit club took a trip to the state fair .There were 59 students and 6 chaperones, and the total admission cost for the group was 508$.Student tickets cost 2$ more than the chaperone tickets.Write an equation to represent the cost of a student ticket
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Ответ:
Step-by-step explanation:
First you determine the variables x and y as:
x: the value for student tickets
y: the value for chaperone tickets.
Knowing that student tickets cost $ 2 more than companion tickets, it is represented by the equation:
x= y +2
On the other hand, there were 59 students and 6 companions. And the total cost of admission for the group was $ 508, that is to say that what all the students and the companions have paid adds up to $ 508. Expressed by an equation:
59x + 6y = 508
Then the system of equations to solve and thus obtain the price of a student ticket and the price of a companion ticket is:
Solving for x, the price of a student ticket:
Rearranging the first equation,
y = x - 2
Replacing in the second equation and solving for x:
59*x + 6*(x -2)=508
59*x + 6*x -12=508
65*x -12=508
65*x= 508 +12
65*x= 520
x=8
The cost of a student ticket is 8$
Ответ:
0.5 < x < 3
or (0.5, 3)
Step-by-step explanation:
-16t² + 56t + 2 = 26
Subtract both sides by 26
-16t² + 56t + 2 = 26
-26 -26
-16t² + 56t - 24 = 0
Divide both sides by -8 to simplify
(-16t² + 56t - 24)/8 = 0/8
2t² - 7t + 3 = 0
Factor
(x - 3)(2x - 1) = 0
Do this to find the x's
x - 3 = 0
+ 3 +3
x = 3
2x - 1 = 0
+ 1 + 1
2x = 1
2x/2 = 1/2
x = 0.5
0.5 < x < 3
This means the intervals will have to be between 0.5 and 3 seconds